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1、(3x-3)/(x-2)+(x-5)/(x-8)=(3x-9)/(x-4)+(x-3)/(x-6) (3x-3)/(x-2)-(3x-9)/(x-4)=(x-3)/(x-6)-(x-5)/(x-8) 3[(x-1)/(x-2) -(x-3)/(x-4）]=(x-3)/(x-6)-(x-5)/(x-8) 左右同时通分得 3[(x-1)(x-4)-(x-3)(x-2)]/(x-2)(x-4)=[(x-3)(x-8)-(x-5)(x-6)]/(x-6)(x-8) 3（x²-5x+4-x²+5x-6)/(x-2)(x-4) =(x²-11x+24-x²+11x-30)/(x-6)(x-8) 3×（-2）/(x-2)(x-4)=（-6）/(x-6)(x-8) 1/(x-2)(x-4)=1/(x-6)(x-8) (x-2)(x-4)=(x-6)(x-8) x²-6x+8=x²-14x+48 -6x+14x=48-8 8x=40 x=5。
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